Description
Given an integer array nums
, return an array answer
such that answer[i]
is equal to the product of all the elements of nums
except nums[i]
.
The product of any prefix or suffix of nums
is guaranteed to fit in a 32-bit integer.
You must write an algorithm that runs in O(n)
time and without using the division operation.
Example 1:
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| Input: nums = [1,2,3,4]
Output: [24,12,8,6]
|
Example 2:
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| Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]
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Constraints:
2 <= nums.length <= 10^5
-30 <= nums[i] <= 30
- The product of any prefix or suffix of
nums
is guaranteed to fit in a 32-bit integer.
Solutions
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| class Solution {
public:
vector<int> productExceptSelf(vector<int>& nums) {
int length = nums.size();
vector<int> L(length, 0), R(length, 0);
vector<int> answer(length);
L[0] = 1;
for (int i = 1; i < length; i++) {
L[i] = nums[i - 1] * L[i - 1];
}
R[length - 1] = 1;
for (int i = length - 2; i >= 0; i--) {
R[i] = nums[i + 1] * R[i + 1];
}
for (int i = 0; i < length; i++) {
answer[i] = L[i] * R[i];
}
return answer;
}
};
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