Description
You are given an integer array height
of length n
. There are n
vertical lines drawn such that the two endpoints of the ith
line are (i, 0)
and (i, height[i])
.
Find two lines that together with the x-axis form a container, such that the container contains the most water.
Return the maximum amount of water a container can store.
Notice that you may not slant the container.
Example 1:
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| Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
|
Example 2:
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| Input: height = [1,1]
Output: 1
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Constraints:
n == height.length
2 <= n <= 10^5
0 <= height[i] <= 10^4
Solutions
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| class Solution {
public:
int maxArea(vector<int>& height) {
int i = 0;
int j = height.size() - 1;
int res = 0;
while (i < j) {
res = height[i] < height[j] ? max(res, (j - i) * height[i++])
: max(res, (j - i) * height[j--]);
}
return res;
}
};
|